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- Path: rz.uni-karlsruhe.de!not-for-mail
- From: Olaf Leb <leb@iswws1.bau-verm.uni-karlsruhe.de>
- Newsgroups: comp.sys.amiga.hardware
- Subject: Re: CV64 Confusion
- Date: Fri, 12 Jan 1996 10:51:23 +0100
- Organization: ISWW
- Message-ID: <30F62F1B.90F@iswws1.bau-verm.uni-karlsruhe.de>
- References: <820932613.19400@alladin.demon.co.uk> <9601071603.AA0014b@burst.demon.co.uk> <1671.6582T1060T406@telnetwork.it>
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- Francesco Meani wrote:
- >
- > In article: <9601071603.AA0014b@burst.demon.co.uk> Lee Huggett
- > <Lee@burst.demon.co.uk> writes:
- >
- > >: WhiteKnight in UK recently sent me specs (1 page) on CV64.
- > >: It says that it can do upto 1280x1024 in 8bit and 800x600 in 24 bit NI
- > >: 1600x1200 in 8bit and 1024x768 in 24 bit Interlace.
- > >:
- > >: Is this true?
- > >:
- > >: Can I do the following?
- > >:
- > >: 800x600 in 24bit. NI. With 2 or 4Mb RAM?
- > >: 1024x768 in 8 bit. NI. With 2 or 4Mb RAM?
- > >: 1024x758 in 24 bit. NI. With 2 or 4MB RAM?
- >
- > >800x600 in 24 bit 2meg is possible I run Photogenics in this res...
- >
- > >1024x768x256, again yup that is what I run WB in.. again in 2 meg
- >
- > >1024x768x24.... Hmm not sure...you might need 4 meg for this one...
- >
- > 800* 600* 8/8 = 480.000 bytes
- > 1024* 768* 8/8 = 786.432 bytes
- > 1280*1024* 8/8 = 1.310.720 bytes
- > 1600*1200* 8/8 = 1.920.000 bytes
- > 800* 600*24/8 = 1.440.000 bytes
- > 1024* 768*24/8 = 2.359.296 bytes
- > 1280*1024*24/8 = 3.932.160 bytes
- ^^
- You are wrong with the 24Bit-Modes. The CV64 uses 32Bit internally
- (24Bit-Color + 8Bit-Alpha-Channel).
-
- >
- > These are the amount of VRAM required on CV for the above screensize and depth.
- >
- > BTW: 4mb cards also allows you to drag completly 16-24bit screens.
- >
-